A.Down by the bow
B.Down by the stern
C.Down by either the bow or stern
D.In level trim
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A.concentrated high and the double bottoms empty
B.concentrated low and the double bottoms empty
C.evenly distributed vertically with the double bottoms full
D.concentrated and with the double bottoms full
A.down by the head
B.down by the stern
C.inclined due to off-center weight
D.inclined due to wind
A.decrease in KM is equal to the loss of draft
B.virtual rise of G is directly proportional to the remaining draft
C.lost buoyancy method is used to calculate KM，and KB is reduced
D.displacement lost acts at the point where the ship is aground
A.large GM
B.high center of gravity
C.excessive free surface
D.small GZ
A.at
B.in
C.on
D.to
最新試題
Angular motion about the vertical axis of a vessel is called（）.
For a vessel inclined by the wind，multiplying the buoyant force by the horizontal distance between the lines of action of the buoyant and gravity forces gives the（）.
On a vessel proceeding from a very cold to a warm climate with a cargo of a nonhygroscopic nature in the holds，which is TRUE?（）.
If the metacentric height is large，a floating vessel will（）.
The KM for a vessel may be determined by which of the following?（）.
During counterflooding to correct a severe list or trim aggravated by an off-center load，a ship suddenly takes a list or trim to the opposite side. You should（）.
Horizontal transverse motion of a vessel is known as（）.
If the metacentric height is small，a floating vessel will（）.
Broken stowage must be reduced to（）.
In order to determine the trimming arm for your vessel at any particular draft，which of the following would you compare?（）.