A. dividing the total longitudinal moment summation by displacement
B.dividing the total vertical moment summation by displacement
C.multiplying the MT1 by the longitudinal moments
D.subtracting LCF from LCB
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A.metacentric height
B.mean draft
C.moment to trim one inch
D.deadweight
A.lower than the center of gravity
B.at the same height as the center of gravity
C.higher than the baseline
D.on the longitudinal centerline
A.free surface effects are reduced due to pocketing
B.KG is reduced as the vessel seeks the angle of loll
C.effective beam is increased causing BM to increase
D.underwater volume of the hull is increased
A.vertically above the center of buoyancy
B.vertically above the center of gravity
C.at the intersection of the upright vertical centerline and the line of action of the buoyant force
D.at the geometric center of the underwater volume
A.The foot／tons needed to trim the vessel by 1 inch
B.The foot／tons needed to trim the vessel by 1 foot
C.The moments needed to trim the vessel by 1 centimeter
D.The amount of vessel will trim when loading 100 tons 100 feet from the tipping Center
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A vessel trimmed by the stern has a（）.
The height of the metacenter above the keel will vary depending on the（）.
（）we have worked out the loading plan，we shall start doing more revision work.
A ship lists and trims about the（）.
A vessel’s KG is determined by（）.
A continual worsening of the list or trim indicates（）.
A floating vessel will behave as if all of its weight is acting downward through the（）.
A vessel with a large GM will（）.
A serious loss of reserve buoyancy resulting from flooding any compartment of a ship will always（）.
GM cannot be used as an indicator of stability at all angles of inclination because（）.